TEC Papago · Geometry 1 · Unit 1

1.4 Rotations

Turning a figure about the origin

Standards: G-CO.A.4 · G-CO.A.5

A locksmith cuts a spare key and hands it back the wrong way round. It still fits — the teeth are in the same places, the key has just been turned.

A different shop hands back a key that looks right until you try it. Same shape, mirrored. That one will never work.

Both are rigid — nothing stretched, nothing shrank. But one is a turn and the other is a flip, and only one of them still opens the door.

Which of the two could you fix by turning it over?

Given a point or figure and a rotation angle about the origin, you will produce the image and check it by applying the inverse rotation.

Definitions and rules

Rotation about the origin

R90(x, y) = (−y, x) R180(x, y) = (−x, −y) R270(x, y) = ( y, −x)

All counter-clockwise, all about the origin.

Why it has to be this: a quarter turn sends the horizontal axis onto the vertical one, so x and y swap roles and one of them changes sign.

Why 180° is the one to remember

R180 just negates both coordinates — no swapping. It is the easiest to recall and the easiest to check.

And 90° applied three times equals 270°, so if you remember only the quarter turn you can always get the rest.

Worked examples

Example 1 — a whole triangle through 270°

Rotate triangle A(2, −1), B(4, 2), C(−1, 3) by 270° counterclockwise about the origin.

Suggested work

Givens

A(2, −1) B(4, 2) C(−1, 3) R270 about the origin

Tools

R270(x, y) = (y, −x)

Primitives

Use the same rule on every vertex.

Computation

A(2, −1) → A′(−1, −2) B(4, 2) → B′(2, −4) C(−1, 3) → C′(3, 1)

Notice: Each ordered pair swaps roles, then the original x changes sign.

Why the rule has this form

A 270° counterclockwise turn is a 90° clockwise turn. The axes exchange roles, and the new y points opposite the original x direction.

Example 2 — recovering a preimage from its rotated image

P′(−5, 2) is the image of P after a 90° counterclockwise rotation about the origin. Find P.

Suggested work

Givens

R90(P) = P′ P′(−5, 2)

Tools

The inverse of R90 is R270. R270(x, y) = (y, −x)

Primitives

x = −5 y = 2

Computation

R270(−5, 2) = (2, 5) Check: R90(2, 5) = (−5, 2) = P′ Therefore P = (2, 5).

Notice: Undo a rotation with the turn that completes the full 360° cycle.

Why the inverse check works

R90 followed by R270 totals 360°, which returns every point to its starting location.

Example 3 — a quarter turn

Rotate P(3, 4) by 90° counter-clockwise about the origin.

Suggested work

Givens

P(3, 4) 90° counter-clockwise, about the origin

Tools

R90(x, y) = (−y, x)

Primitives

x = 3 y = 4

Computation

R90(3, 4) = (−(4), (3)) = (−4, 3)

Notice: the coordinates swapped places, then one changed sign.

Common traps

Clockwise 90° is R270

The label R90 in this book means 90° counterclockwise. A 90° clockwise turn follows R270(x, y) = (y, −x). The broken assumption is treating the angle size as enough information while ignoring direction.

Practice

  1. Rotate R(4, −7) by 180° about the origin.

    Answer — tap to show

    R′(−4, 7)

    Suggested work — tap to show

    Givens

    R(4, −7) 180° about the origin

    Tools

    R180(x, y) = (−x, −y)

    Primitives

    x = 4 y = −7

    Computation

    R180(4, −7) = (−(4), −(−7)) = (−4, 7)
  2. Rotate Q(3, 2) by 270° counterclockwise about the origin.

    Answer — tap to show

    Q′(2, −3).

  3. Rotate Q(−2, 5) by 90° counter-clockwise about the origin.

    Answer — tap to show

    Q′(−5, −2)

    Suggested work — tap to show

    Givens

    Q(−2, 5) 90° CCW about the origin

    Tools

    R90(x, y) = (−y, x)

    Primitives

    x = −2 y = 5

    Computation

    R90(−2, 5) = (−(5), (−2)) = (−5, −2)
  4. Rotate segment MN with endpoints M(−2, 1) and N(3, 1) by 90° counterclockwise about the origin.

    Answer — tap to show

    M′(−1, −2) and N′(−1, 3).

    Suggested work — tap to show

    Givens

    M(−2, 1) N(3, 1) R90

    Tools

    R90(x, y) = (−y, x)

    Primitives

    Apply the rule to both endpoints.

    Computation

    M(−2, 1) → M′(−1, −2) N(3, 1) → N′(−1, 3)
  5. A classmate is asked to rotate S(4, 1) by 90° clockwise and writes S′(−1, 4). Diagnose the error and give the correct image.

    Answer — tap to show

    They used the counterclockwise R90 rule. A 90° clockwise turn uses R270, so S′(1, −4).

    Suggested work — tap to show

    Givens

    S(4, 1) 90° clockwise classmate wrote S′(−1, 4)

    Tools

    90° clockwise = R270 R270(x, y) = (y, −x)

    Primitives

    x = 4 y = 1

    Computation

    R270(4, 1) = (1, −4) Their result, (−1, 4), comes from R90(4, 1).